Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20 (suggested in the article "Dynamic Ride Sharing: Theory and Practice"†). (Round your answer to three decimal places.) (a) What is the probability that the number of drivers will be at most 18?

Answer:Step-by-step explanation:Given that the number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20 (suggested in the article "Dynamic Ride Sharing: Theory and Practice"†).a) [tex]P(X\leq 15) = 0.1565=0.157[/tex]b) [tex]P(X>26) =1-F(26)\\= 1-0.9221\\=0.0779=0.078[/tex]c) [tex]P(15\leq x\leq 26)\\=F(26)-F(14)\\=0.9221-0.1049\\=0.8172=0.817[/tex]d) 2 std dev = 2(20) =40Hence 2 std deviation means20-40, 20+40i.e. (0,60)[tex]P(0<x<60)\\=F(60)-F(0)\\=1-0.00000206\\=0.99999794=1.000[/tex]